P. Herbert vs H. Mayot

Pierre-Hugues Herbert

1.91=52%W: 80%

At odds of 1.91, the implied probability is 52%. Over the last 2 years, Pierre-Hugues Herbert has won 80% of his 10 matches at comparable odds.

Harold Mayot

1.91=52%W: 0%

At odds of 1.91, the implied probability is 52%. Over the last 2 years, Harold Mayot has won 0% of his 11 matches at comparable odds.