Botic Van De Zandschulp vs Alexander Shevchenko

Botic Van De Zandschulp

1.50=67%W: 55%

At odds of 1.50, the implied probability is 67%. Over the last 2 years, Botic Van De Zandschulp has won 55% of his 31 matches at comparable odds.

Alexander Shevchenko

2.63=38%W: 50%

At odds of 2.63, the implied probability is 38%. Over the last 2 years, Alexander Shevchenko has won 50% of his 22 matches at comparable odds.