Alex De Minaur vs Stan Wawrinka

Alex De Minaur

1.10=91%W: 89%

At odds of 1.10, the implied probability is 91%. Over the last 2 years, Alex De Minaur has won 89% of his 196 matches at comparable odds.

Stan Wawrinka

7.00=14%—

Unusual position for Stan Wawrinka: not enough historical data at odds close to 7.00 over the last 3 years. The market lacks a concrete reference at this level for this player.