Alexander Zverev vs Botic Van De Zandschulp

Alexander Zverev

1.11=90%W: 86%

At odds of 1.11, the implied probability is 90%. Over the last 2 years, Alexander Zverev has won 86% of his 228 matches at comparable odds.

Botic Van De Zandschulp

6.50=15%—

Unusual position for Botic Van De Zandschulp: not enough historical data at odds close to 6.50 over the last 3 years. The market lacks a concrete reference at this level for this player.