| S1 | S2 | |
|---|---|---|
 A. de Minaur(1) | 6 | 6 |
C. Hewitt(Q) | 2 | 3 |
| Temps (min) | 29 | 32 |
Alex De MinaurAt odds of 1.07, the implied probability is 93%. Over the last 2 years, Alex De Minaur has won 90% of his 177 matches at comparable odds.
Cruz HewittUnusual position for Cruz Hewitt: not enough historical data at odds close to 9.00 over the last 3 years. The market lacks a concrete reference at this level for this player.
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